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pel-ee Brekeke Junior Member
Joined: 29 Oct 2008 Posts: 6
Location: Ukraine
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Posted: Wed Oct 29, 2008 9:17 am Post subject: ARS conf |
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1. Brekeke Product Name and version: Brekeke PBX, Version 2.1.6.6
2. Java version:
3. OS type and the version:
4. UA (phone), gateway or other hardware/software involved:
5. Select your network pattern from http://www.brekeke-sip.com/bbs/network/networkpatterns.html :
6. Your problem:
There is a problem.
How to connect two ippbx to be able to communicate among themselves?
Such as the one pbx numbers begin with 7, while the other 2.
Both pbx are in the same subnet.
where and what to prescribe in order to be able to call?
Thanks |
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hope Brekeke Master Guru
Joined: 15 Jan 2008 Posts: 862
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Posted: Wed Oct 29, 2008 11:14 am Post subject: |
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make an ARS - pattern OUT at pbx numbers begin with 7
matching patterns:
To: sip:(2.+)@
Deploy patterns:
To: sip:$1@ the other pbx IP
at the pbx numbers begin with 2
matching patterns:
To: sip:(7.+)@
Deploy patterns:
To: sip:$1@ the other pbx IP
you can also use dial plan |
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pel-ee Brekeke Junior Member
Joined: 29 Oct 2008 Posts: 6
Location: Ukraine
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Posted: Thu Oct 30, 2008 2:55 am Post subject: |
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Thank Hope
With the settings that you recommended the return errors 407
Proxy Authentification Required.
I solved the problem this way:
on the PBX B (rooms start at 2) created a number of 700 (or any other) and at the PBX A (Rooms start at 7) wrote that ARS
pattern OUT
matching patterns
from sip:(7.+)@
to sip:(2.+)@
deploy pattens
from sip:700@
to sip:$1@ip pbx b
Once again, thank you |
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